Logic Test 6

[victor barry]

A teacher in a primary school, play's a game with her students, called the remainder game, to help them practice their long division.
Every student know's the rules:
1) pick 2 numbers, where at least one has exactly 3 digits.
2) write the smaller number below the larger, and divide it into the larger number, writing the remainder below the numbers. If the remainder is zero, you are finished, but if not, you must divide the bottom number into the number just above it, again, writing the remainder below the numbers
e.g.: 124
5
4
1
0.
3) Once a child has a zero remainder he's finished. The teacher gives each child one sweet for each remainder they have, including zero. So that child would have gotten 3 sweets(for 4,1,0).
4)If there's a mistake in the workings the child get's no sweets.

One day, every child get's a different number of sweets.This would not be possible had another child been playing too. How many sweets did the teacher give out that day???

[CocoPops]

ten ?

[ELNINO 9]

10000000000000000000000000000

[Mark79]

Obviously a piss take as none of this makes any sense whatsoever.

There is feck all logic to this logic test.

[pondus]

A teacher in a primary school, play's a game with her students, called the remainder game, to help them practice their long division.
Every student know's the rules:
1) pick 2 numbers, where at least one has exactly 3 digits.
2) write the smaller number below the larger, and divide it into the larger number, writing the remainder below the numbers. If the remainder is zero, you are finished, but if not, you must divide the bottom number into the number just above it, again, writing the remainder below the numbers
e.g.: 124
5
4
1
0.
3) Once a child has a zero remainder he's finished. The teacher gives each child one sweet for each remainder they have, including zero. So that child would have gotten 3 sweets(for 4,1,0).
4)If there's a mistake in the workings the child get's no sweets.

One day, every child get's a different number of sweets.This would not be possible had another child been playing too. How many sweets did the teacher give out that day???

[victor barry]

Obviously a piss take as none of this makes any sense whatsoever.

There is feck all logic to this logic test.

Of coarse there's logic to it- you just need to be a small bit smart to figure it out, so maybe you shouldn't even try!!!!!!

[Vermilion]

Of coarse there's logic to it- you just need to be a small bit smart to figure it out, so maybe you shouldn't even try!!!!!!

Horses for.. er coarses?.

[Sisterstiffticket]

**** me geez...Life's just too short!

[victor barry]

I'm gonna give the solution tonight on Cork talks back, on red fm, for all you corkonians. So remember, for the show, where it's your opinion that counts tune into 106 fm from 9-12 sunday- thursday.

[Mark79]

Of coarse there's logic to it- you just need to be a small bit smart to figure it out, so maybe you shouldn't even try!!!!!!

Whoops!! Actually its 'course' not 'coarse'. So, a small bit smart, that would be you then??!!

OK so when do we get to find out the answer on here?

[victor barry]

Well to be honest, I thought there was a mathematician on this forum, but as there obviously isn't, I'll give the solution:
Instead of starting with the numbers the child thinks of you should start with the remainders, and construct the sequence backwards.
If I divide a by b and my remainder is c, then a=c+kb, where k, is the amount of times, b divided into a. As we are looking to maximize the length of the sequence, we should always let k=1. So the sequence will go as follows:
0,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,159 7.......We can stop now, as one of the childs numbers must have 3 digits. So if a child picks 1597 and 987, they'll win the maximum amount sweets, provided they dont make any mistakes (these aren't the only numbers that will give the maximum amount of sweets). Having chosen these numbers the child will have 15 remainders, and any number of remainders below this is also possible.As they all win a different amount of sweets, we know the answer is the sum of the integers between 1 and 15. So you can add up every integer, between 1 and 15, but if you're a genius like me, you'll know that you can save time, as the formula for the sum of the sequence of consecutive integers between 1and "n" is given by n(n+1)/2, or in our case 15(16)/2 = 15(8)=120.
So the answer is 120.




You're welcome.

[Migselv]

Well to be honest, I thought there was a mathematician on this forum, but as there obviously isn't, I'll give the solution:
Instead of starting with the numbers the child thinks of you should start with the remainders, and construct the sequence backwards.
If I divide a by b and my remainder is c, then a=c+kb, where k, is the amount of times, b divided into a. As we are looking to maximize the length of the sequence, we should always let k=1. So the sequence will go as follows:
0,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,159 7.......We can stop now, as one of the childs numbers must have 3 digits. So if a child picks 1597 and 987, they'll win the maximum amount sweets, provided they dont make any mistakes (these aren't the only numbers that will give the maximum amount of sweets). Having chosen these numbers the child will have 15 remainders, and any number of remainders below this is also possible.As they all win a different amount of sweets, we know the answer is the sum of the integers between 1 and 15. So you can add up every integer, between 1 and 15, but if you're a genius like me, you'll know that you can save time, as the formula for the sum of the sequence of consecutive integers between 1and "n" is given by n(n+1)/2, or in our case 15(16)/2 = 15(8)=120.
So the answer is 120.




You're welcome.

I only see one problem here. You posted this in the "Jokes, Links & Funnies" section. But it wasn't a joke, wasn't a link and it wasn't funny.






























* just kidding mate

[pondus]

I only see one problem here. You posted this in the "Jokes, Links & Funnies" section. But it wasn't a joke, wasn't a link and it wasn't funny.






























* just kidding mate

Four friends have been doing really well in their calculus class: they have been getting top grades for their homework and on the midterm. So, when it's time for the final, they decide not to study on the weekend before, but to drive to another friend's birthday party in another city - even though the exam is scheduled for Monday morning. As it happens, they drink too much at the party, and on Monday morning, they are all hung over and oversleep. When they finally arrive on campus, the exam is already over.
They go to the professor's office and offer him an explanation: "We went to our friend's birthday party, and when we were driving back home very early on Monday morning, we suddenly had a flat tire. We had no spare one, and since we were driving on backroads, it took hours until we got help."
The professor nods sympathetically and says: "I see that it was not your fault. I will allow you to make up for the missed exam tomorrow morning."
When they arrive early on Tuesday morning, the students are put by the professor in a large lecture hall and are seated so far apart from each other that, even if they tried, they had no chance to cheat. The exam booklets are already in place, and confidently, the students start writing.
The first question - five points out of one hundred - is a simple exercise in integration, and all four finish it within ten minutes.
When the first of them has completed the problem, he turns over the page of the exam booklet and reads on the next one:





















Problem 2 (95 points out of 100): Which tire went flat?



There, a math joke

[victor barry]

Four friends have been doing really well in their calculus class: they have been getting top grades for their homework and on the midterm. So, when it's time for the final, they decide not to study on the weekend before, but to drive to another friend's birthday party in another city - even though the exam is scheduled for Monday morning. As it happens, they drink too much at the party, and on Monday morning, they are all hung over and oversleep. When they finally arrive on campus, the exam is already over.
They go to the professor's office and offer him an explanation: "We went to our friend's birthday party, and when we were driving back home very early on Monday morning, we suddenly had a flat tire. We had no spare one, and since we were driving on backroads, it took hours until we got help."
The professor nods sympathetically and says: "I see that it was not your fault. I will allow you to make up for the missed exam tomorrow morning."
When they arrive early on Tuesday morning, the students are put by the professor in a large lecture hall and are seated so far apart from each other that, even if they tried, they had no chance to cheat. The exam booklets are already in place, and confidently, the students start writing.
The first question - five points out of one hundred - is a simple exercise in integration, and all four finish it within ten minutes.
When the first of them has completed the problem, he turns over the page of the exam booklet and reads on the next one:





















Problem 2 (95 points out of 100): Which tire went flat?



There, a math joke

What was the integration question?

[Sisterstiffticket]

There, a math joke

Please please please...can we all go back to saying the word MATHS!