The draw was a FIX

[Rich]

right, brain has worked a bit more...

it depends if the draw came out of the hat exactly the same i.e:

12 34 56 78 (teams being 1-8)

or whether you'd say

34 56 78 12 is in fact the same draw.....

Makes a BIG difference on the number of permutations...

[Rich]

So it's 8! divide by something...

[MattB]

But, the teams could have been drawn either way, with lfc vs arsenal or arsenal vs lfc. WOuld be the same result from 2 permutations.

Plus arsenal and Liverpool could have come out second to last and last, rather than first and second. Same draw, but a different permutation...

[Rich]

I'm gonna guess 8!/4!

As there are four games.

Therefore:

1,680 permutations

[MattB]

So it's 8! divide by something...

Possibly 4! as this would account for the number of different orders in which each set of ties could be drawn. But that's a guess

Beat me to it ^^^

[Rich]

Which explains the four team.

4!/2! = 12

[Rich]

Glad we sorted this fine mess out.

So was it a fix?

[Barnyard]

Glad we sorted this fine mess out.

So was it a fix?

Well thanks to your 'Mathsterbation' we know its pretty unlikely to have been a lucky guess!

[Shaggy]

I'm gonna guess 8!/4!

As there are four games.

Therefore:

1,680 permutations

1680 permutations. What a bally good guess that was then, eh! Cor. Great guess.



I think it's naive to think UEFA wouldn't fix a draw like this.

[Jack D Rips]

A yankee which is a four horse bet has 6 doubles

I'll get me coat

[Hansi]

There are 105 possible draws; 7*5*3=105

[MattB]

Glad we sorted this fine mess out.

So was it a fix?

1/1068 chance of guessing it, which is better than the stupidity tax. However the odds of posting it in the way it was posted (i.e. this is the fixed draw), 1.5 hours before the draw and being correct must be astronomical

[Shaggy]

There are 105 possible draws; 7*5*3=105

Slightly less impressive, but still a ****ing good guess.

[Rich]

There are 105 possible draws; 7*5*3=105

Expand! I'm not giving you full marks for that!

[MrMichael]

There are 105 possible draws; 7*5*3=105

I think thats right